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:: Time-work-solved-2
Question: A can do a certain job in 12 days.B is 60% more
 efficient than A. How many days does B alone take to do the same job?

Solution:
B will do the same work in (12*100)/160= 7.5 days

Question: 45 men can complete a work in 16 days. 
Six days after they started working, 30 more men joined them. 
How many days will they now take to complete the remaining work?

Solution:
After six days:
45*10=75*x     
X=6 days

Question: A is twice as good a workman as B and together 
they ?nish a piece of work in 18 days. The number of days taken by A alone to ?nish the work is:

Solution:
A=2B (work)
3B works in 18 days so B will do the same in (18*3)=54 days
hence A will do it in 54/2=27 days
Together they will take 42/(1+2)=14 days

Question: A and B can Complete a work in 15 days and 
10 days respectively. They started doing the work together 
but  after 2 days B had to leave and A alone completed the 
remaining work. The whole work was completed in:

Solution:
A and B can complete whole work in

30/(2+3)=6 days
Part of work completed together in

3 days =2/6=1/3 part
Now 2/3 part will be completed by A in

2/3*15=10 days
Hence, whole work will be completed in

2+10=12 days


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